9x^2-12x+36=73

Solution for 9x^2-12x+36=73 equation:

9x^2-12x+36=73

We move all terms to the left:

9x^2-12x+36-(73)=0

We add all the numbers together, and all the variables

9x^2-12x-37=0

a = 9; b = -12; c = -37;
Δ = b2-4ac
Δ = -122-4·9·(-37)
Δ = 1476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1476}=\sqrt{36*41}=\sqrt{36}*\sqrt{41}=6\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-6\sqrt{41}}{2*9}=\frac{12-6\sqrt{41}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+6\sqrt{41}}{2*9}=\frac{12+6\sqrt{41}}{18}
$